Trivial but here it is:
Cantor offered an elegant pictorial proof of the countability of the rationals. Here is a less-pictorial proof.
It is rather easy to see that one can form a set of n rationals from the number n. For example, for n =3, we have
{1}, {1/2, 2/2}, {1/3, 2/3, 3/3}
We are unconcerned that n/n = 1 produces n 1's or about such equalities as 2/4 = 1/2.
So, for any finite n, the number of ratios is
1 + 2 + 3 + ... + n
or n(n+1)/2
So just as we can put the positive integers into 1:1 correspondence with their squares,
1 2 3 4 5
1 4 9 16 25
so can we put the positive integers into 1:1 correspondence with the number of ratios, as defined, up to n.
1 2 3 4 5
1 3 6 10 15
The remainder of the proof is by routine induction.
Note that since n(n+1)/2 - n(n-1)/2 = n, all we need do is add n(n+1)/2 + (n+1) to get (n+1)(n+2)/2.
With a base case of k=1, we may generalize, by use of induction, to make our proof airtight with proof that the two sequences remain 1:1 ad infinitum.
We leave it as an exercise for the reader to show that all real rationals, including negatives, are countable.
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